Question 770
A Layer 2 pseudowire carries bridged customer IPv6 traffic. Observed: IPv6 frames fail while ordinary IPv4 packets cross the same circuit. After the correction, which result would most convincingly show that this fault is resolved?
Explanation
Correct Answer
After remove unjustified payload filtering and use proper Ethernet-transparent pseudowire mapping, inspect whether both IPv4 and IPv6 EtherTypes cross according to the customer contract. This closes the loop between the reported observation (IPv6 frames fail while ordinary IPv4 packets cross the same circuit) and the underlying issue (The service has an inappropriate ethertype filter or nontransparent encapsulation).
Incorrect Answers
This result is useful in another case with evidence Only the outer service VLAN survives and nested customer tags are lost. It does not test recovery from ipv6 frames fail while ordinary ipv4 packets cross the same circuit. Check instead whether both IPv4 and IPv6 EtherTypes cross according to the customer contract.
It confirms an unrelated service correction: The attachment circuit and pseudowire do not share a compatible effective MTU. The present case reports IPv6 frames fail while ordinary IPv4 packets cross the same circuit. Its completion test is Both IPv4 and IPv6 EtherTypes cross according to the customer contract.
That observation would verify a separate fault involving the site's vpls nlri or rt export settings are incomplete. Its symptom is One site never joins the full mesh despite a healthy BGP session. For this case the actual issue is the service has an inappropriate ethertype filter or nontransparent encapsulation, and the relevant success signal is Both IPv4 and IPv6 EtherTypes cross according to the customer contract.